Home >Backend Development >C#.Net Tutorial >How to pass pointer as parameter to method in C#?
To pass a pointer as a parameter to a method, see the following steps -
First, create a function exchange using the unsafe modifier.
public unsafe void swap(int* p, int *q) { int temp = *p; *p = *q; *q = temp; }
Now under static void main, add the values of the first and second variables, setting pointers for them.
Display the value of the variable and then call the swap() method shown above. This method exchanges values and displays the result -
public unsafe static void Main() { Program p = new Program(); int var1 = 10; int var2 = 20; int* x = &var1; int* y = &var2; Console.WriteLine("Before Swap: var1:{0}, var2: {1}", var1, var2); p.swap(x, y); Console.WriteLine("After Swap: var1:{0}, var2: {1}", var1, var2); Console.ReadKey(); }
The above is the detailed content of How to pass pointer as parameter to method in C#?. For more information, please follow other related articles on the PHP Chinese website!