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PHP error: Unable to reassign non-variable reference, solution!
Introduction:
In the process of using PHP to develop projects, we often encounter various error messages. One of the common errors is "PHP Warning: Can't re-assign non-variable by reference". This error usually occurs when we try to reassign a reference to a non-variable to another variable. This article explains the cause of this problem and provides a solution.
Cause of the problem:
In PHP, you can set a variable to a reference to another variable through the reference assignment operator (= &). This can be useful in certain situations, such as when passing function arguments or traversing arrays. However, when we try to reassign a reference to a non-variable to another variable, an error occurs.
Solution:
To solve this problem, we can take the following methods:
For example, suppose we have a function that returns a reference to an object. We can define it as a variable and then reassign it:
$object = get_object(); $objRef = &$object; $anotherObject = get_another_object(); $objRef = &$anotherObject; // 此时不会报错
For example:
$object = get_object(); $objRef = &$object; unset($objRef); $anotherObject = get_another_object(); $objRef = &$anotherObject; // 不会报错
Summary:
In PHP development, when we try to reassign the reference of a non-variable to another variable, "PHP Warning: Can't re-assign non-" will appear variable by reference" error. In order to solve this problem, we can define non-variable references as variables, use the unset() function to destroy the references, or redesign the code logic to avoid the reallocation of references.
By adopting these solutions, we can better handle this common PHP error and improve our code quality and development efficiency.
References:
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