Home >Backend Development >Golang >How to solve golang error: cannot refer to unexported name 'x' in package 'y', solution strategy

How to solve golang error: cannot refer to unexported name 'x' in package 'y', solution strategy

PHPz
PHPzOriginal
2023-08-20 16:30:331399browse

如何解决golang报错:cannot refer to unexported name \'x\' in package \'y\',解决策略

How to solve golang error: cannot refer to unexported name 'x' in package 'y'

In the process of using golang development, we may encounter this Error: "cannot refer to unexported name 'x' in package 'y'". This error is mainly caused when we access unexported variables or functions.

In golang, the case of the first letter of variable and function names determines their visibility. An identifier is exportable if its first letter is an uppercase letter; if its first letter is a lowercase letter, it is not exportable. Non-exportable variables or functions can only be accessed within the same package and cannot be directly accessed by other packages. When we try to access unexported variables or functions in other packages, the above error will occur.

So, how to solve this problem? The following are several solution strategies:

  1. Change the variable or function to export: If we need to access a variable or function in other packages, then we can change its first letter to a capital letter , so it can be exported. For example, if we have a variable named "x" that is not accessible outside the package, we can change it to "X".

Code example:

package y

var x string // 不可导出的变量

func foo() {
    // 不可导出的函数
}

Modified code:

package y

var X string // 可导出的变量

func Foo() {
    // 可导出的函数
}
  1. Access within the same package: If we cannot change the variable or function If it is exported but needs to be used in other packages, you can indirectly access this variable or function by providing a function inside the same package. In this way, other packages can get the required results by calling this function.

Code example:

package y

var x string // 不可导出的变量

func getX() string {
    return x
}

Called in other packages:

package main

import (
    "fmt"
    "package/y"
)

func main() {
    x := y.getX()
    fmt.Println(x)
}
  1. Use interfaces to hide implementation details: If there are some private types in a package ( The first letter is lowercase), but we hope that other packages can only call public methods when using them. We can encapsulate these private types as interfaces and expose this interface in a public way. In this way, other packages can only access these types through the interface, but cannot directly access the private methods or properties of their implementation objects.

Code example:

package y

type privateType struct {
    data int
}

func (p *privateType) privateMethod() {
    fmt.Println(p.data)
}

type PublicInterface interface {
    PublicMethod()
}

func CreatePrivateType() PublicInterface {
    return &privateType{}
}

func (p *privateType) PublicMethod() {
    p.privateMethod()
}

Used in other packages:

package main

import (
    "package/y"
)

func main() {
    p := y.CreatePrivateType()
    p.PublicMethod() // 可以调用
    p.privateMethod() // 无法调用,报错
}

Through the above solutions, we can solve the golang error: "cannot refer to unexported name 'x' in package 'y'". Choosing the appropriate strategy according to the specific situation can make our code more readable, maintainable, and improve code reusability.

The above is the detailed content of How to solve golang error: cannot refer to unexported name 'x' in package 'y', solution strategy. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn