How to convert json string to php object

To convert a JSON string into a PH object, you can use the built-in function "json_decode()". The usage method is: 1. Create a PHP sample file; 2. Define a JSON string variable "$jsonString"; 3. . Call the "json_decode()" function to decode the string variable into the PHP object "$phpObject"; 4. Use "$phpObject->property" to access the object's property value.

Operating system for this tutorial: Windows 10 system, php8.1.3 version, Dell G3 computer.

To convert a JSON string into a PHP object, you can use the built-in function json_decode(). This function decodes a JSON string into PHP data types, including objects, arrays, and scalar values.

Here is an example that shows how to convert a JSON string into a PHP object:

$jsonString = '{"name": "John", "age": 30, "city": "New York"}';
// 将 JSON 字符串转换为 PHP 对象
phpObject=jsondecode(phpObject = json_decode(phpObject=jsondecode(jsonString);
// 使用转换后的 PHP 对象
echo $phpObject->name;  // 输出：John
echo $phpObject->age;   // 输出：30
echo $phpObject->city;  // 输出：New York

In the above example, we have a JSON containing name, age and city string. By calling json_decode() and passing the JSON string as argument, we decode it into a PHP object $phpObject.

After that, we can use $phpObject->property to access the property value of the object just like accessing ordinary objects.

It should be noted that if the JSON string contains an array instead of an object, json_decode() will decode it into an associative array by default. If you want to get the index array, you can set the second optional parameter of json_decode() to true, that is, json_decode($jsonString, true).

In addition, json_decode() also provides other options and parameters for controlling decoding behavior. You can check the PHP documentation for more details about the json_decode() function.

The above is the detailed content of How to convert json string to php object. For more information, please follow other related articles on the PHP Chinese website!