


PHP function introduction—is_resource()
: Check whether a variable is a resource
In PHP, is_resource()
is a very useful function for Determine whether a variable is a resource type. Resource types are used in PHP to represent external resources, such as database connections, file handles, image resources, etc. This article will introduce the use of the is_resource()
function in detail and demonstrate its practical application through code examples.
is_resource()
The syntax of the function is as follows:
bool is_resource ( mixed $var )
Among them, $var
represents the variable to be checked. This function returns a Boolean value, true
indicates that the variable is a resource, false
indicates that the variable is not a resource.
The following uses several specific examples to illustrate the usage of the is_resource()
function.
- Check whether the file handle variable is a resource
$file = fopen("data.txt", "r"); if (is_resource($file)) { echo "文件句柄为资源类型"; } else { echo "文件句柄不是资源类型"; } fclose($file);
The above code first uses the fopen()
function to open a file and returns the file handle Assign a value to variable $file
. Then, check whether $file
is a resource type through the is_resource()
function. If it is a resource type, output "the file handle is a resource type"; otherwise, output "the file handle is not a resource type". Finally, use the fclose()
function to close the file handle.
- Check whether the database connection variable is a resource
$host = "localhost"; $user = "root"; $pass = "password"; $dbname = "test"; $conn = mysqli_connect($host, $user, $pass, $dbname); if (is_resource($conn)) { echo "数据库连接为资源类型"; } else { echo "数据库连接不是资源类型"; } mysqli_close($conn);
In the above code, first use the mysqli_connect()
function to connect to the database and return the The database connection is assigned to variable $conn
. Then, check whether $conn
is a resource type through the is_resource()
function. If it is a resource type, output "the database connection is a resource type"; otherwise, output "the database connection is not a resource type". Finally, use the mysqli_close()
function to close the database connection.
- Check whether the image resource variable is a resource
$width = 500; $height = 300; $image = imagecreatetruecolor($width, $height); if (is_resource($image)) { echo "图像资源为资源类型"; } else { echo "图像资源不是资源类型"; } imagedestroy($image);
In the above code, use the imagecreatetruecolor()
function to create a true color with specified width and height image, and assign the returned image resource to the variable $image
. Then, check whether $image
is a resource type through the is_resource()
function. If it is a resource type, output "Image resource is a resource type"; otherwise, output "Image resource is not a resource type". Finally, use the imagedestroy()
function to destroy the image resource.
Through the above code examples, we can clearly understand the specific application scenarios of the is_resource()
function when determining whether a variable is a resource type. When we need to operate external resources, we can use this function to ensure that the variables being operated are valid resources and avoid errors.
Summary:
In this article, we introduce the use of the PHP function is_resource()
in detail, and demonstrate the practical application of this function in three situations through code examples. Through the is_resource()
function, we can easily determine whether a variable is a resource type and perform corresponding processing as needed. I hope this article will be helpful to everyone in the process of PHP resource processing.
The above is the detailed content of PHP function introduction—is_resource(): Check whether the variable is a resource. For more information, please follow other related articles on the PHP Chinese website!

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