Home  >  Article  >  Backend Development  >  Use the path/filepath.Ext function to get the extension part of the file path

Use the path/filepath.Ext function to get the extension part of the file path

WBOY
WBOYOriginal
2023-07-25 20:42:261306browse

Use the path/filepath.Ext function to obtain the extension part of the file path

During the programming process, we often encounter the need to obtain the extension of the file. Go language provides a very convenient function path/filepath.Ext to implement this function. This article explains how to use this function to get the extension part of a file path.

First, let us look at a simple example:

package main

import (
    "fmt"
    "path/filepath"
)

func main() {
    filePath := "/Users/username/Documents/example.txt"
    ext := filepath.Ext(filePath)
    fmt.Println("文件扩展名为:", ext)
}

In the above code, we define a filePath variable to represent the path of the file. Then, use the filepath.Ext function to get the extension part of the file path and assign the result to the ext variable. Finally, use the fmt.Println function to print out the file extension.

Run the above code, the output result is:

文件扩展名为: .txt

As can be seen from the output result, we successfully obtained the extension of the file path using the path/filepath.Ext function.

It should be noted that the path/filepath.Ext function will only return the extension part after the last .. If the file path contains multiple ., only the part after the last . will be returned. For example, if the file path is "/Users/username/Documents/example.tar.gz", the extension returned will be ".gz" instead of ".tar.gz". This function will always return extensions starting with ..

In addition, if the file path does not contain ., an empty string will be returned. For example, if the file path is "/Users/username/Documents/example", then the returned extension will be "" (empty string).

In addition to getting the extension of the file path, the path/filepath.Ext function can also be used to determine whether the file has a specific extension. For example, we can use the following code to determine whether a file is an image file:

package main

import (
    "fmt"
    "path/filepath"
)

func main() {
    filePath := "/Users/username/Documents/example.jpg"
    ext := filepath.Ext(filePath)
    isImage := (ext == ".jpg" || ext == ".png" || ext == ".gif")
    fmt.Println("是否为图片文件:", isImage)
}

In the above code, we compare the file extension with ".jpg", ".png", ".gif" " to determine whether a file is an image file. If it is an image file, the value of isImage is true, otherwise it is false.

Through the above example, we can see that using the path/filepath.Ext function is very simple, and we can easily get the extension part of the file path. Whether it is used to obtain the extension or determine the file type, this function is a very practical tool.

The above is the detailed content of Use the path/filepath.Ext function to get the extension part of the file path. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn