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How to use PHP and CGI to develop a video sharing website
With the development of the Internet, video sharing websites have become an important way for people to obtain information and entertainment. If you have a certain understanding of website development, then using PHP and CGI to develop a video sharing website is a good choice. This article will introduce how to use PHP and CGI to implement a simple video sharing website and provide some code examples.
The following is a simple user form example:
CREATE TABLE users ( id INT PRIMARY KEY AUTO_INCREMENT, username VARCHAR(50) NOT NULL, password VARCHAR(50) NOT NULL, email VARCHAR(50) NOT NULL, created_at DATETIME NOT NULL );
The following is a simple user registration code example:
<?php if ($_SERVER['REQUEST_METHOD'] == 'POST') { $username = $_POST['username']; $password = $_POST['password']; $email = $_POST['email']; // 验证用户输入 // 将用户数据存储到数据库中 $sql = "INSERT INTO users (username, password, email, created_at) VALUES ('$username', '$password', '$email', NOW())"; // 执行数据库查询 // 提示用户注册成功 echo "注册成功!"; } ?>
The following is a simple video upload code example:
<?php if ($_SERVER['REQUEST_METHOD'] == 'POST') { $title = $_POST['title']; $file = $_FILES['video']['tmp_name']; // 生成一个唯一的文件名 $filename = uniqid() . '.mp4'; // 将视频文件保存到服务器上 move_uploaded_file($file, 'videos/' . $filename); // 将视频信息存储到数据库中 $sql = "INSERT INTO videos (title, filename, created_at) VALUES ('$title', '$filename', NOW())"; // 执行数据库查询 // 提示用户上传成功 echo "上传成功!"; } ?>
The following is a simple video playback and comment code example:
<?php // 获取视频ID $id = $_GET['id']; // 查询视频信息 $sql = "SELECT * FROM videos WHERE id = $id"; // 执行数据库查询 // 显示视频播放器 echo "<video src='videos/$filename' controls></video>"; // 查询评论信息 $sql = "SELECT * FROM comments WHERE video_id = $id"; // 执行数据库查询 // 显示评论列表 while ($row = mysqli_fetch_assoc($result)) { echo "<div>{$row['content']}</div>"; } // 显示评论表单 echo "<form action='comment.php' method='POST'> <textarea name='content'></textarea> <input type='hidden' name='video_id' value='$id'> <input type='submit' value='评论'> </form>"; ?>
Through the above steps, we can use PHP and CGI to implement a simple video sharing website. Of course, this is just a starting point, you can expand the functionality of the website and beautify the interface of the website according to your needs. I hope this article is helpful to you, and I wish you success in development!
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