*p 1 and *(p 1) The differences are: 1. Different priorities. In p 1, p will be dereferenced first, while in *(p 1), p 1 will be calculated first; 2 , the operation objects are different, p 1 is to dereference p first, and (p 1) is to add p to 1 first; 3. The results are different, p 1 is to add 1 to the value of the object pointed to by p, (p 1) is to add 1 to the value of the object pointed to by p. The value of the next object.
The operating environment of this tutorial: Windows 10 system, DELL G3 computer.
What is the difference between *p 1 and *(p 1)? I believe that many netizens are still not clear about it. Today, the editor has brought you relevant tutorials, hoping to help you.
1. Different priorities
p 1 and (p 1) have different operation priorities. In C/C, operators (dereference operator) and (addition operator) have different precedence. The addition operator has lower precedence than the dereference operator. Therefore, in p 1, p will be dereferenced first, and then 1 will be added; in *(p 1), because adding parentheses changes the priority, p 1 will be calculated first and then dereferenced.
2. Different operation objects
The objects operated by p 1 and (p 1) are also different. p 1 first dereferences p, gets the object pointed to by p, and then adds 1 to the object. And (p 1) first adds 1 to p to point to the next object, and then dereferences the new object.
3. The results are different
The results of p 1 and (p 1) are different. p 1 first dereferences p and then adds 1, so the result is the value of the object pointed to by p plus 1. And (p 1) adds 1 to p and then dereferences it, so the result is the value of the next object pointed to by p.
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