Home  >  Article  >  Java  >  Java Error: Array Initialization Error, How to Solve and Avoid

Java Error: Array Initialization Error, How to Solve and Avoid

WBOY
WBOYOriginal
2023-06-24 12:46:371066browse

When writing Java programs, arrays are one of the commonly used data structures. However, if you initialize the array incorrectly, your program will not run properly. This article will introduce the causes, solutions, and tips for avoiding such errors in array initialization in Java.

1. Causes of array initialization errors

Array initialization errors are usually caused by the following reasons:

  1. Array out of bounds

When trying When accessing a location in the array that does not exist, an array out-of-bounds error occurs. For example:

int[] arr = new int[10];
System.out.println(arr[10])  // 数组下标越界
  1. Wrong array size

If the array size is incorrect or does not match, an initialization error will occur. For example:

int[] arr = new int[] {1, 2, 3};
int[] arr2 = new int[2];
arr2 = arr;  // 错误的数组大小

should look like this:

int[] arr = new int[] {1, 2, 3};
int[] arr2 = new int[arr.length];
arr2 = arr;
  1. Type mismatch

If you try to store values ​​of different types in the same array when initializing the array , a type mismatch error will occur. For example:

int[] arr = new int[] {1, 2, "3"};  // 类型不匹配

should be like this:

String[] arr = new String[] {"1", "2", "3"};

2. How to solve the array initialization error

  1. Array out-of-bounds error

If an array occurs Out-of-bounds errors can be solved by using try-catch statements in the program. Alternatively, you can add conditional restrictions to determine whether the array subscript is out of bounds to avoid exceptions.

int[] arr = new int[10];
try {
    System.out.println(arr[10]);
} catch (IndexOutOfBoundsException e) {
    System.out.println("数组下标越界");
}
  1. Wrong array size

When declaring and initializing an array, make sure the array is the correct size and suitable for storing the data your program needs.

int[] arr = new int[] {1, 2, 3};
int[] arr2 = new int[arr.length];  // 相同大小的数组
arr2 = arr;
  1. Type mismatch

When initializing an array, make sure that all elements are values ​​of the same type. If you need to use values ​​of different types, use an array of objects.

Object[] arr = new Object[] {1, 2, "3"};  // 对象数组

3. How to avoid array initialization errors

In order to avoid array initialization errors, you need to master the following skills:

  1. Avoid hard-coding array sizes

Hard-coded array size refers to specifying a fixed number when the array is declared. This approach is error-prone, so programmatically calculated array sizes should always be used.

int[] arr = new int[calculateSize()];  // 使用方法calculateSize()返回的大小
  1. Use predefined variables

When initializing the array, use predefined variables to represent the array size or other properties.

final int ARRAY_SIZE = 10;
int[] arr = new int[ARRAY_SIZE];  // 预定义变量
  1. Using Java Collections

In Java, collections provide a flexible, extensible way to store and manipulate data. Compared to arrays, collections are better suited for handling dynamic data. Therefore, in some cases it may be better to use Java collections.

List<Integer> arr = new ArrayList<Integer>();
arr.add(1);
arr.add(2);
arr.add(3);

Conclusion

In Java programming, it is important to avoid mistakes. Array is one of the important data structures in Java. Incorrect array initialization will cause the program to fail to run normally. Therefore, such mistakes need to be understood and avoided. Such errors can be more easily found and corrected by using techniques such as using predefined variables, avoiding hard coding, and using Java collections.

The above is the detailed content of Java Error: Array Initialization Error, How to Solve and Avoid. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn