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PHP Warning: mysql_free_result() expects parameter 1 to be resource solution
When using PHP to connect to the MySQL database, the result set obtained by executing the query statement needs to be released using the function mysql_free_result(). to avoid memory leaks. But sometimes we encounter this error message: PHP Warning: mysql_free_result() expects parameter 1 to be resource. What's the problem? how should I solve this?
Let’s first analyze the meaning of this error message: mysql_free_result() expects the first parameter passed in to be a resource type value. What is the resource type? In PHP, using the mysql_query() function to execute a query statement will return a value of the result set resource type. In other words, the return value of the mysql_query() function, which is the value of the result set resource type, should be passed in the first parameter passed into the mysql_free_result() function.
If we encounter this error message, it means that the correct parameter is not passed in the first parameter passed into the mysql_free_result() function. This parameter should actually be the result set resource type returned by the mysql_query() function. value. Therefore, this error message reminds us that we need to check whether the mysql_query() function is used correctly in the code and confirm that its return value is indeed a resource type value.
To solve this problem, we need to start from two aspects: one is to check the code, and the other is to understand the usage specifications of the mysql_query() function.
2.1 Check the code
When checking the code, we need to find the mysql_query() function and mysql_free_result() function, and whether the parameters passed between these two functions are correct. If there is a problem with the parameters passed, an error will be reported. We need to confirm the following points in the code:
If there are no problems with the above points, then it is likely that the result set resource returned by the mysql_query() function is invalid. At this time, we need to carefully observe the usage specifications of the mysql_query() function.
2.2 Understand the usage specifications of the mysql_query() function
The first thing to note is that the mysql_query() function was deprecated after PHP 5.5.0 and was deprecated after PHP 7.0.0. delete. It is currently recommended to use the mysqli_query() function or PDO's prepare() and execute() functions instead. Therefore, we need to be careful when using the mysql_query() function to try to avoid problems, or use the safer and more stable mysqli_query() function or PDO's prepare() and execute() functions.
Secondly, it should be noted that the result set resource type value returned by the mysql_query() function is only valid when the function is called, and only when the query statement is not a SELECT statement, a non-resource type value will be returned. value. Therefore, we need to confirm whether the mysql_query() function is used correctly in the code and check whether the value returned is a resource type value.
Finally, what you need to know is that the value of the result set resource type returned by the mysql_query() function will be automatically released as long as the mysql_query() function is executed. Therefore, if we execute the mysql_free_result() function immediately after the mysql_query() function returns the result set, a parameter type error will occur.
In summary, in order to avoid the error PHP Warning: mysql_free_result() expects parameter 1 to be resource, we need to pay attention to the following points when using the mysql_query() function:
In short, when using PHP to connect to the MySQL database, we need to pay attention to comply with the specifications, avoid errors, and ensure the correctness and stability of the code.
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