1. Question
Array slicing is a method of obtaining a subarray of a given array. Suppose, a[] is an array. It has 8 elements, indexed from a[0] to a[7]
int a[] = {8, 9, 4, 6, 0, 11, 45, 21}
We need to find a subset of the array index, ranging from a[3] to a[6]. startIndex corresponds to a[3], and endIndex corresponds to a[6]. Therefore, we get the following slice
a[] = {6, 0, 11, 45}
There are three ways to find the slice of an array:
By copying elements
By using the copyOfRange() method
-
Using Java 8 streams
2. Method
1) By copying the elements
First, we find the start and end index of the given array.
After that, we create an empty array (slice array) of size (endIndex - startIndex).
From the given array, copies the elements (from startIndex) to the slice array. Finally, print the slice array.
public class Test { public static void main(String[] args) { int[] array = {0,1,2,3,4,5,6,7,8,9}; int startIndex = 3, endIndex = 8; int[] slicedArray = getSlice(array, startIndex, endIndex + 1); System.out.println("Slice of Array: "+ Arrays.toString(slicedArray)); } public static int[] getSlice(int[] array, int startIndex, int endIndex) { int[] slicedArray = new int[endIndex - startIndex]; //将数组元素从原始数组复制到新创建的切片数组 for (int i = 0; i < slicedArray.length; i++) { slicedArray[i] = array[startIndex + i]; } return slicedArray; } }
The results are as follows:
Slice of Array: [3, 4, 5, 6, 7, 8]
2) By using the copyOfRange() method
copyOfRange()
Method belongs toJava Arrays
class.It copies
the specified range of the array into a newly created array (slice array)
and returns the newly created array containing the specified range from the original array.Creating an array slice takes O(n) time, and storing elements requires
O(n)
space, where n is the number of elements in the result array.
public static int[] copyOfRange(int[] original, int from, int to)
It throws the following exception:
ArrayIndexOutOfBoundsException
: If from is less than 0 or from is greater than the length of the specified array .IllegalArgumentException
: If the argument from is greater than to.NullPointerException
: If the given array is empty.
public class Test { public static void main(String[] args) { int[] array = {0,1,2,3,4,5,6,7,8,9}; int startIndex = 3, endIndex = 8; int[] slicedArray = getSlice(array, startIndex, endIndex + 1); System.out.println("Slice of Array: "+ Arrays.toString(slicedArray)); } public static int[] getSlice(int[] array, int startIndex, int endIndex) { int[] slicedArray = Arrays.copyOfRange(array, startIndex, endIndex); return slicedArray; } }
The result is as follows:
Slice of Array: [3, 4, 5, 6, 7, 8]
3) Using Java 8 Streams
By using the following steps
We can find slices of arrays using Java 8 Stream.
First, find the startIndex and endIndex arrays.
Use the range() method to convert elements (within a range) to the original stream.
Use the map() method to map the specified element in the specified array.
Convert the mapped array to an array by calling the toArray() method. Print slice
public class Test { public static void main(String[] args) { int[] array = {0,1,2,3,4,5,6,7,8,9}; int startIndex = 3, endIndex = 8; int[] slicedArray = getSlice(array, startIndex, endIndex + 1); System.out.println("Slice of Array: "+ Arrays.toString(slicedArray)); } public static int[] getSlice(int[] array, int startIndex, int endIndex) { //获取数组的切片并将其存储在数组 slcarray[] 中 // range() 方法将元素转换为流 // 使用 lambda 表达式获取 int 流的元素 // 使用 toArray() 方法将映射元素转换为切片数组 int[] slcarray = IntStream.range(startIndex, endIndex).map(i -> array[i]).toArray(); return slcarray; } }
The result is as follows:
Slice of Array: [3, 4, 5, 6, 7, 8]
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