What are extends T and super T in Java?

? Wildcard type

• ##d203bb1ae585225d4838a2b7e3d0503e indicates the upper bound of the type, indicating that the parameterized type may be T or a subclass of T;

• 117c5a0bdb71ea9a9d0c2b99b03abe3e represents the lower bound of the type (called super type qualification in Java Core), indicating that the parameterized type is the super type (parent type) of this type, until Object;

The upper bound88479397f227fb27352acb086031f211

List3f622c4eabd1145a5b9f71573034350b means "a list with any type inherited from Son" , the compiler cannot determine the type held by the List, so it cannot safely add objects to it. You can add null because null can represent any type. So the add method of List cannot add any meaningful elements, but it can accept existing subtype List assignments.

You may try to do this:

List<? extends Father> list = new LinkedList<Son>();
list.add(new Son());

Even if you specify the Son type, you cannot add a Son object using the add method. Why can't the Father class and the subclasses of the Father class be added to the

list? Let's analyze it.

List3f622c4eabd1145a5b9f71573034350b means that the upper limit is Father, and the following assignments are legal

   List<? extends Father> list1 = new ArrayList<Father>();
   List<? extends Father> list2 = new ArrayList<Son>();
   List<? extends Father> list3 = new ArrayList<LeiFeng>();

If List3f622c4eabd1145a5b9f71573034350b supports the add method:

list1 can add Father and all subclasses of Father;

• list2 can add Son and all subclasses of Son;

• list3 can add LeiFeng and all LeiFeng subclasses.

• The following code does not pass compilation:

list1.add(new Father());//error
list1.add(new Son());//error

The reason is that the compiler only knows that the container is Father or its derived class, but it does not know the specific type. . Maybe Father? Maybe Son? Maybe LeiFeng, XiaoMing? After the compiler sees that Father is used for assignment later, the parameter type in the collection is not limited to "Father". Instead, it is marked with a placeholder: CAP#1 to indicate capturing a Father or a subclass of Father. I don’t know the specific class, but the code is CAP#1. Then whether you want to insert Son, LeiFeng or Father compiler, you don't know whether it can match this CAP#1, so you won't allow it.

So the difference between wildcard 6b3d0130bba23ae47fe2b8e8cddf0195 and type parameters is that to the compiler, all T represents the same type. For example, in the following generic method, the three T's all refer to the same type, either String or Integer.

public <T> List<T> fill(T... t);

But the wildcard 6b3d0130bba23ae47fe2b8e8cddf0195 does not have such a constraint. List6b3d0130bba23ae47fe2b8e8cddf0195 simply means: there is something in the collection, and I don’t know what it is.

So the error here is that nothing can be put in List3f622c4eabd1145a5b9f71573034350b.

List3f622c4eabd1145a5b9f71573034350b list cannot be added, but this form is still very useful. Although the add method cannot be used, a Season can specify different types during initialization. For example:

List<? extends Father> list1 = getFatherList();//getFatherList方法会返回一个Father的子类的list

In addition, since we have ensured that the Father class or one of its subclasses is stored in the List, you can use the get method to directly obtain the value:

List<? extends Father> list1 = new ArrayList<>();
Father father = list1.get(0);//读取出来的东西只能存放在Father或它的基类里。
Object object = list1.get(0);//读取出来的东西只能存放在Father或它的基类里。
Human human = list1.get(0);//读取出来的东西只能存放在Father或它的基类里。
Son son = (Son)list1.get(0);

Lower bound< ;? super T> does not affect storage in, but retrieval can only be placed in the Object object.

The lower bound is declared with super, indicating that the parameterized type may be the specified type, or this type Parent type, up to Object.

//super只能添加Father和Father的子类，不能添加Father的父类,读取出来的东西只能存放在Object类里
List<? super Father> list = new ArrayList<>();
list.add(new Father());
list.add(new Human());//compile error 
list.add(new Son());
Father person1 = list.get(0);//compile error 
Son son = list.get(0);//compile error 
Object object1 = list.get(0);

Because the lower bound specifies the lower limit of the minimum granularity of the element, it actually relaxes the type control of the container element. Since the element is the base class of Father, it can be stored in a granularity smaller than that of Father. For type safety reasons, we can add a Father object or any of its subclasses (such as Son). However, since the compiler does not know which superclass of Father the content of the List is, it is not allowed to add any specific superclass. Class (such as Human). And when we read it, the compiler can only return the Object object without knowing what type it is, because Object is the ultimate ancestor class of any Java class. But in this case, all the type information of the element is lost.

PECS Principle

Finally, let’s take a look at what is the PECS (Producer Extends Consumer Super) principle. It is already well understood:

Frequent external reading For content, it is suitable to use the upper bound Extends.

• If you often insert it in, Nether Super is suitable.

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