How to parse json object array in php

With the rapid development of Internet technology, various new applications continue to emerge. For back-end development, data interaction is becoming more and more important. Among them, the JSON (JavaScript Object Notation) format has become a widely used data exchange format. It is lightweight and easy to understand and process, so it is widely used in various Web projects.

In back-end development, PHP language is also a widely used technology, and parsing JSON object array object array object array object array is also a common problem. Next, this article will introduce how PHP parses JSON object array object array object array object array.

1. Use json_decode() function to parse JSON objects

In PHP, the easiest way to parse JSON objects is through the json_decode() function, which converts the JSON data format into Convert to PHP operable data type. The following is an example:

<?php $json_data = &#39;{"name": "张三", "age": 20, "gender": "男"}&#39;;  // 定义一个JSON数据
$obj = json_decode($json_data);   // 将JSON数据格式转换为PHP对象
print_r($obj);   // 输出转换后的PHP对象
?>

The output of the above code is as follows:

stdClass Object
(
    [name] => 张三
    [age] => 20
    [gender] => 男
)

You can see that the JSON data format is successfully converted into a PHP object through the json_decode() function, and the corresponding properties to access.

2. Use the json_decode() function to parse JSON object arrays

In addition to parsing ordinary JSON objects, sometimes back-end development also faces parsing JSON object arrays. Likewise, this can be easily achieved using the json_decode() function. For example:

<?php $json_data = &#39;[{"name": "张三", "age": 20, "gender": "男"}, {"name": "李四", "age": 18, "gender": "女"}]&#39;;  // 定义一个JSON对象数组
$arr = json_decode($json_data, true);   // 将JSON数据格式转换为PHP数组（注意第二个参数true）
print_r($arr);   // 输出转换后的PHP数组
?>

The output result of the above code is as follows:

Array
(
    [0] => Array
        (
            [name] => 张三
            [age] => 20
            [gender] => 男
        )

    [1] => Array
        (
            [name] => 李四
            [age] => 18
            [gender] => 女
        )

)

You can see that by specifying the second parameter true, the json_decode() function successfully converts the JSON object array into a PHP array, and the array Each element in corresponds to a JSON object.

3. Use json_decode() function to parse JSON object array object array

If you need to parse JSON object array object array, you only need to add another layer on top of the above code Just cycle. For example:

<?php $json_data = &#39;[{"name": "张三", "age": 20, "gender": "男", "books":[{"bookname":"php","price":"20.00"},{"bookname":"mysql","price":"30.00"}]}, {"name": "李四", "age": 18, "gender": "女", "books":[]} ]&#39;;  // 定义一个JSON对象数组对象数组
$arr = json_decode($json_data, true);   // 将JSON数据格式转换为PHP数组（注意第二个参数true）
foreach($arr as $item) {
    echo "姓名：" . $item[&#39;name&#39;] . "；年龄：" . $item[&#39;age&#39;] . "；性别：" . $item[&#39;gender&#39;] . "<br/>";
    echo "书籍列表：<br>";
    foreach($item['books'] as $book) {
        echo "书名：" . $book['bookname'] . "；价格：" . $book['price'] . "<br>";
    }
    echo "<hr>";
}
?>

The output result of the above code is as follows:

姓名：张三；年龄：20；性别：男
书籍列表：
书名：php；价格：20.00
书名：mysql；价格：30.00
------------------------------
姓名：李四；年龄：18；性别：女
书籍列表：
------------------------------

As you can see, in the above code, we successfully parsed the JSON object array object array through two layers of for loops, and based on Data structures present data.

Summary:

To sum up, parsing JSON object array object array object array object array object array in PHP is very simple. You only need to use the json_decode() function to convert the JSON format into Data types that PHP can operate on. When faced with complex data structures, we can use multiple loops to parse and display data. Finally, it is recommended that back-end developers master the skills of JSON format and PHP parsing JSON in order to interact and operate data more efficiently.

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