Home >Backend Development >PHP Tutorial >Yii实现单用户博客系统文章详情页插入评论表单的方法_PHP

Yii实现单用户博客系统文章详情页插入评论表单的方法_PHP

WBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWB
WBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOriginal
2016-05-28 11:49:581338browse

本文实例讲述了Yii实现单用户博客系统文章详情页插入评论表单的方法。分享给大家供大家参考,具体如下:

action部分:

<&#63;php
function test($objs)
{
 $objs->var=10;
}
class one
{
 public $var=1;
}
$obj=new one();
echo $obj->var.'<p>';
test($obj);
echo $obj->var;
exit;

PostController.php页面:

...
/**
* Displays a particular model.
* @param integer $id the ID of the model to be displayed
*/
public function actionView($id)
{
  $post=$this->loadModel($id);
  $comment=$this->newComment($post);
  $this->render('view',array(
    'model'=>$post,
    'comment'=>$comment,
  ));
}
protected function newComment($post)
{
  $comment=new Comment();
  if(isset($_POST['Comment']))
  {
   $comment->attributes=$_POST['Comment'];
   if($post->addComment($comment))//==============================
   {
    if($comment->status==Comment::STATUS_PENDING)
     Yii::app()->user->setFlash('commentSubmitted','Thank you...');
    $this->refresh();
   }
  }
  return $comment;
}
...

models/Post.php页面:

...
public function addComment($comment)
{
  if(Yii::app()->params['commentNeedApproval'])
   $comment->status=Comment::STATUS_PENDING;
  else
   $comment->status=Comment::STATUS_APPROVED;
  $comment->post_id=$this->id;
  return $comment->save();
}
...

post/view.php页面:

...
<div id="comments">
<h3>Leave a Comment</h3>
<&#63;php if(Yii::app()->user->hasFlash('commentSubmitted')): &#63;>
 <div class="flash-success">
 <&#63;php echo Yii::app()->user->getFlash('commentSubmitted'); &#63;>
 </div>
<&#63;php else: &#63;>
 <&#63;php $this->renderPartial('/comment/_form',array(
 'model'=>$comment,
 )); &#63;>
<&#63;php endif; &#63;>
</div><!-- comments -->
...

希望本文所述对大家基于Yii框架的PHP程序设计有所帮助。

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn