How to determine whether a number is an integer in php

Two methods: 1. Use floor() to round, and then compare it with the original number. The syntax is "floor($n)===$n". If they are equal, it is an integer, otherwise it is not an integer. . 2. Use is_int() to detect, the syntax is "is_int($n)", if it returns TRUE, it is an integer, if it returns FALSE, it is not an integer.

The operating environment of this tutorial: windows7 system, PHP7.1 version, DELL G3 computer

php determines a number Two methods to determine whether it is an integer

Method 1: Use floor() to round, and then compare it with the original number

<?php
header(&#39;content-type:text/html;charset=utf-8&#39;);   
$num=3.14;
if(floor($num)===$num){
	echo "是整数";
}else{
	echo "不是整数";
}
?>

Method 2: Use the function is_int() that comes with PHP

The is_int() function is used to detect whether the variable is an integer. TRUE if the specified variable is an integer, FALSE otherwise.

<?php
header(&#39;content-type:text/html;charset=utf-8&#39;);   
$num=3;
if(is_int($num)){
	echo "是整数";
}else{
	echo "不是整数";
}
?>

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