How to find the even sum of an array in php

Method: 1. Use "$s=0;" to define a variable to store the calculation result; 2. Use "foreach($arr as $v){}" to loop through the array; 3. In the loop body , to determine whether the array element value is divisible by 2, just add the divisible elements, the syntax is "if($v%2==0){$s =$v;}".

The operating environment of this tutorial: windows7 system, PHP8.1 version, DELL G3 computer

php finds an even number in an array The sum method

1. Define a variable assigned a value of 0 to store the calculation results.

$s=0;

2. Use the foreach statement to traverse the array

foreach ($array as $value){
    语句块;
}

Traverse the given $array array and assign the value of the current array to $value in each loop.

3. In the loop body, perform parity judgment and summation

You only need to judge whether the array element $value can be divisible by 2, and add the divisible elements. That’s it.

if($value%2!=0){
$s += $value;
}

Implementation code:

<?php
header(&#39;content-type:text/html;charset=utf-8&#39;);   
$arr = [1,2,3,4,5,6,7,8,9,10];
var_dump($arr);
$s=0;
foreach($arr as $v){
	if($v%2==0){
		$s+=$v;
	}
}
echo "数组偶数和为：".$s;
?>

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