Method: 1. Use the "date_format" function, the syntax is "where date_format(date,'%Y-%m-%d')='year-month-day'"; 2. Use the datediff function, Syntax "WHERE(datediff(time,'year-month-day')=0)".
The operating environment of this tutorial: windows10 system, mysql8.0.22 version, Dell G3 computer.
How to query the data of a certain day in mysql
1. DATE_FORMAT function
WHERE(datediff(time,'year-month-day')= The DATE_FORMAT() function is used to display date/time data in different formats.
Syntax
DATE_FORMAT(date,format)
The date parameter is a legal date. format specifies the output format of the date/time.
Examples are as follows:
select * from [table_name] where date_format([date_name],'%Y-%m-%d') = '2022-05-13'
2. DATEDIFF function
DATEDIFF() function returns the number of days between two dates.
Syntax
DATEDIFF(date1,date2)
The date1 and date2 parameters are legal date or date/time expressions.
Examples are as follows:
SELECT * FROM [table_name] WHERE ( datediff ( update_time , '2022-05-13' ) = 0 )
Extended knowledge:
SELECT * FROM [table_name] WHERE substring(Convert(char(10),update_time ,112),1,8)='20220513' SELECT * FROM [table_name] WHERE update_time between '2022-05-13 00:00:00' and '2022-05-13 23:59:59' SELECT * FROM [table_name] WHERE year(update_time ) = 2022 and month(update_time )= 05 and day(update_time ) = 13 SELECT * FROM [table_name] WHERE update_time > '2017-09-27' and update_time < '2022-05-13'
Recommended learning: mysql video tutorial
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