Method: 1. Use "$sum=0;" to define a variable to store the calculation results; 2. Use "foreach($arr as $v){}" to loop through the array; 3. In the loop body, check whether the array elements are an odd number, and if so, add them up. The syntax is "if($v%2!=0){$sum =$v;}".
The operating environment of this tutorial: windows7 system, PHP8.1 version, DELL G3 computer
php seeks the array Method of sum of odd numbers
Implementation idea:
Define a variable assigned value 0 for storage calculation result.
Use the foreach statement to loop through the array
In the loop body, check whether the array elements are odd one by one; if they are odd, add them Get up
How to check odd numbers:
Determine whether the element is divisible by 2, if not, it is an odd number. Syntax:
元素%2!=0
Complete implementation code:
<?php header("Content-type:text/html;charset=utf-8"); $arr=array(1,2,3,4,5,6,7,8,9); var_dump($arr); $sum=0; foreach($arr as $v){ if($v%2!=0){ $sum+=$v; } } echo "数组中奇数元素之和:".$sum; ?>
It can be seen that in the above example, the odd number The elements are: 1, 3, 5, 7, 9. Let’s use the counter to add it up to see if it is 25
ok, correct!
Recommended learning: "PHP Video Tutorial"
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