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jquery implements how many seconds to hide pictures after

青灯夜游
青灯夜游Original
2022-04-20 17:33:011726browse

Implementation method: 1. Use the "$("img").delay(milliseconds).fadeOut()" statement and delay() to set the delay seconds; 2. Use "setTimeout(function(){ $("img").hide(); }, millisecond value);" statement, delayed by a timer.

jquery implements how many seconds to hide pictures after

The operating environment of this tutorial: windows7 system, jquery1.10.2 version, Dell G3 computer.

Sometimes the page needs to add some dynamic effects, using a delay of a few seconds to hide the picture and disappear after displaying it for a specified number of seconds. Here we show you how to use jQuery to set the specified number of seconds (5 seconds) before hiding the picture.

Method 1: Use the .delay() method

Set the img image to hide after being displayed for 5 seconds.

<!DOCTYPE html>
<html>
	<head>
		<meta charset="utf-8">
		<script src="js/jquery-1.10.2.min.js"></script>
		<script>
			$(document).ready(function() {
				$("button").click(function() {
					$("img").delay(5000).fadeOut();
				});
			});
		</script>
	</head>
	<body>
		<img  src="img/1.jpg"    style="max-width:90%" / alt="jquery implements how many seconds to hide pictures after" >
		<br><br>
		<button>实现5秒后隐藏图片</button>

	</body>
</html>

jquery implements how many seconds to hide pictures after

Method 2: Use setTimeout() Method

Use setTimeout() to set a timer to hide after 5 seconds of display picture.

<!DOCTYPE html>
<html>
	<head>
		<meta charset="utf-8">
		<script src="js/jquery-1.10.2.min.js"></script>
		<script>
			$(document).ready(function() {
				$("button").click(function() {
					setTimeout(function() { $("img").hide(); }, 5000);
				});
			});
		</script>
	</head>
	<body>
		<img  src="img/1.jpg"    style="max-width:90%" / alt="jquery implements how many seconds to hide pictures after" >
		<br><br>
		<button>实现5秒后隐藏图片</button>

	</body>
</html>

jquery implements how many seconds to hide pictures after

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