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How to remove newline characters in javascript

WBOY
WBOYOriginal
2022-01-12 14:37:4711869browse

In JavaScript, you can use the replace() method to remove newlines. This method is used to replace characters in a string, or to replace a substring that matches a regular expression. The syntax is "testStr.replace( /[\r\n]/g,"")".

How to remove newline characters in javascript

The operating environment of this tutorial: Windows 10 system, JavaScript version 1.8.5, Dell G3 computer.

How to remove line breaks in javascript

In different operating systems, the carriage return and line feed symbols are different, see below:

In Unix system, the end of each line is only "08ab8c7a5e8c3561646c85afea6ee002", which is "\n"; in Windows system, the end of each line is "ae50841a1e5ebedcd2097f872623918408ab8c7a5e8c3561646c85afea6ee002", which is "\n" r\n"; in Mac system, the end of each line is "148abe006775c52e28d07bbe171fd752", which is "\r".

Thereplace() method is used to replace some characters with other characters in a string, or replace a substring that matches a regular expression.

Syntax

stringObject.replace(regexp/substr,replacement)

Parameter Description

regexp/substrRequired. A RegExp object that specifies the substring or pattern to be replaced.

Note that if the value is a string, it is retrieved as a literal text pattern, rather than first being converted to a RegExp object.

replacement Required. A string value. Specifies functions for replacing text or generating replacement text.

Return value

A new string obtained by replacing the first match or all matches of regexp with replacement.

response = response.replace(/\r|\n/ig,"");

Line terminator: A line terminator is a sequence of one or two characters that marks the end of a line for a sequence of input characters. The following codes are recognized as line terminators:

New line (line feed) character ('\n'),

followed by a carriage return character ("\r\n" "),

Separate carriage return character ('\r'),

Next line character ('\u0085'),

line separator ('\u2028 ') or

paragraph separator ('\u2029).

So, taking into account line terminators and their escaped forms, the most guaranteed approach is

str.replaceAll("(\n|\r|(\r\n) |(\u0085)|(\u2028)|(\u2029))", "")

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