In mysql, you can use the "SELECT" statement and the "INNER JOIN" keyword to query the intersection and find the intersection data. The syntax is "SELECT field name FROM data table 1 INNER JOIN data table 2 USING (field name) ;".
The operating environment of this tutorial: windows7 system, mysql8 version, Dell G3 computer.
Create two tables
CREATE TABLE `object_a` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `oname` varchar(50) DEFAULT NULL, `odesc` varchar(50) DEFAULT NULL, `create_time` datetime DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1
Add data
##
CREATE TABLE `object_b` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `oname` varchar(50) DEFAULT NULL, `odesc` varchar(50) DEFAULT NULL, `create_time` datetime DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1Add data
Query intersection
SELECT a.oname,a.odesc FROM object_a a INNER JOIN object_b b ON a.oname=b.oname AND a.odesc=b.odescis equivalent to
SELECT a.oname,a.odesc FROM object_a a INNER JOIN object_b b USING(oname,odesc)The result is as follows
PS: You can try this writing method for other databases
SELECT oname,odesc FROM object_a INTERSECT SELECT oname,odesc FROM object_b[Related recommendations:
mysql video tutorial]
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