MySQL small exercise: How to query all the data on the third to last day in the table

                                                                                                               

To query all employees with the third to last joining date in the employee table, we must take into account the employees who joined on the same day, so use to remove duplicates and first find out the third to last date , and then use this date To query all equal employee information

SELECT
    *FROM
    `employees`WHERE
    `hire_date` = (
        SELECT DISTINCT
            `hire_date`
        FROM
            `employees`
        ORDER BY
            `hire_date` DESC
        LIMIT 2,
        1)

CREATE

drop table if exists `employees`;CREATE TABLE `employees` (`emp_no` int(11) NOT NULL,`birth_date` date NOT NULL,`first_name` varchar(14) NOT NULL,`last_name` varchar(16) NOT NULL,`gender` char(1) NOT NULL,`hire_date` date NOT NULL,)

INSERT

INSERT INTO `employees` (
    `emp_no`,
    `birth_date`,
    `first_name`,
    `last_name`,
    `gender`,
    `hire_date`)VALUES
    (
        1,
        '2021-08-04',
        'Georgi',
        'Facello',
        'M',
        '1980-06-21'
    );INSERT INTO `employees` (
    `emp_no`,
    `birth_date`,
    `first_name`,
    `last_name`,
    `gender`,
    `hire_date`)VALUES
    (
        2,
        '2021-08-20',
        'Bezalel',
        'Simnel',
        'F',
        '1985-11-21'
    );INSERT INTO `employees` (
    `emp_no`,
    `birth_date`,
    `first_name`,
    `last_name`,
    `gender`,
    `hire_date`)VALUES
    (
        3,
        '2021-08-20',
        'Parto',
        'Bamford',
        'M',
        '1986-08-28'
    );INSERT INTO `employees` (
    `emp_no`,
    `birth_date`,
    `first_name`,
    `last_name`,
    `gender`,
    `hire_date`)VALUES
    (
        4,
        '2021-08-20',
        'Chirstian',
        'Koblick',
        'M',
        '1986-12-01'
    );

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