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How to debug sql statement errors in php: 1. Debug PHP SQL errors through the die statement; 2. Debug PHP SQL errors through the "mysql_error" statement.
The operating environment of this article: windows7 system, PHP7.1 version, DELL G3 computer
How to debug sql statement errors in php?
Debug PHP SQL errors through die and mysql_error statements
1. Code
<!--处理文件代码--> <?php $conn=mysql_connect('localhost','root','root') or die("与服务器连接失败!"); mysql_select_db('db_database22',$conn) or die("没有找到数据库!"); if($_POST[Submit]=="提交"){ $admin=$_POST[admin];//获取提交的用户名 $pass=$_POST[pass];//获取提交的密码 $dates=date("Y-m-d H:i:s");//定义当前时间 $query="insert into user (admin,password,dates) values('$admin','$pass','$dates')";//编写添加语句 $result=mysql_query($query,$conn) or die(mysql_error()); //执行添加语句,并返回错误信息 if($result){ echo "<script>alert('添加成功!'); window.location.href='index.php';</script>"; }else{ echo "添加失败!!"; } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=gb2312" /> <title>SQL语句错误</title> </head> <style type="text/css"> <!-- .STYLE1 {color: #FF0000} --> </style> <body> <!--表单提交页,设置的表单元素--> <form name="form1" method="post" action="index.php"> <table width="240" border="1" cellpadding="1" cellspacing="1" bordercolor="#FFFFFF" bgcolor="#FF0000"> <tr> <td width="80" align="right" bgcolor="#FFFFFF"><span class="STYLE1">管理员:</span></td> <td width="147" bgcolor="#FFFFFF"><input name="admin" type="text" id="admin" size="20"></td> </tr> <tr> <td align="right" bgcolor="#FFFFFF"><span class="STYLE1">密码:</span></td> <td bgcolor="#FFFFFF"><input name="pass" type="password" id="pass" size="20"></td> </tr> <tr> <td colspan="2" align="center" bgcolor="#FFFFFF"><input type="submit" name="Submit" value="提交"></td> </tr> </table> </form> </body> </html>
2. Running results
Unknown column 'password' in 'field list'
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