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php method to remove js: first create a PHP sample file; then use the PHP regular expression "preg_replace($preg,"",$str,3);" to remove the js code.
#The operating environment of this article: Windows7 system, PHP7.1, Dell G3 computer.
php uses regular replacement to filter out the js (script) code
Use the preg_replace regular matching function in php to filter out the js code in the web page, in preg_replace() The fourth parameter indicates the number of replacements. The default is -1, which means replacing all. If you only want to replace 2 times, you can write preg_replace($p1,$p2,$p3,2).
The matching rule cannot use "/
Source code example:
<?php header("Content-type:text/html;charset=utf-8"); $str = '<script type="text/javascript" src="dd.js"></script> 测试php正则匹配掉js代码测试php正则匹配掉js代码测试php正则匹配掉js代码测试php正则匹配掉js代码测试php正则匹配掉js代码测试php正则匹配掉js代码 <script type="text/javascript" src="123.js"></script> <script type="text/javascript"> var aa = "sdsds"; alert(aa); </script>
Test PHP regular matches js code';
$preg = "/<script[\s\S]*?<\/script>/i"; $newstr = preg_replace($preg,"",$str,3); //第四个参数中的3表示替换3次,默认是-1,替换全部 echo $newstr; ?>
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