How to print rhombus with for loop in c language

C language for loop printing diamond method: use two for loops to implement conditional judgment, the code is [int i,j;for(i=0; i=n-i-1&&j

C language for loop printing diamond method:

Method 1 (printing mainly with loop )

#include <stdio.h> 
void print(int n) 
{ 
    int i,j; 
    for(i=1; i<=n; i++) 
    { 
        for(j=1; j<=n-i; j++) 
        { 
            printf(" "); 
        } 
        for(j=n-i+1; j<n+i; j++) 
        { 
            printf("*"); 
        } 
        printf("\n"); 
    } 
     
    for(i=n-1; i>=1; i--) 
    { 
        for(j=1; j<=(n-i); j++) 
        { 
            printf(" "); 
        } 
        for(j=n-i+1; j<n+i; j++) 
        { 
            printf("*"); 
        } 
        printf("\n"); 
    } 
} 
 
void main() 
{ 
    int n; 
    printf("---------开始打印符号---------\n"); 
    printf("请输入数字:"); 
    scanf("%d",&n); 
    print(n); 
    printf("---------结束打印符号---------\n");     
}

Method 2: (Two fors, judge and implement based on conditions)

#include <stdio.h> 
//输出格式 
void print(char ch) { 
    putchar(ch); 
} 
//星号 
void printstar(int n) 
{ 
    int i,j;    //行，列 
    for(i=0; i<2*n-1; i++) 
    { 
        for(j=0; j<2*n-1; j++) 
        { 
            if(i<n) 
            { 
                if(j>=n-i-1&&j<n+i) 
                { 
                    print(&#39;*&#39;); 
                } 
                else 
                { 
                    print(&#39; &#39;); 
                } 
            } 
            else 
            { 
                if(j>=i-n+1&&j<3*n-i-2) 
                { 
                    print(&#39;*&#39;); 
                } 
                else  
                { 
                    print(&#39; &#39;); 
                } 
            } 
 
        } 
        print(&#39;\n&#39;); 
    } 
} 
 
void main() 
{ 
    int n; 
    printf("---------开始打印符号---------\n"); 
    printf("请输入数字:"); 
    scanf("%d",&n); 
    printstar(n); 
    printf("---------结束打印符号---------\n");     
}

Explanation: (2n-1)—(n-i-1) = n i

( 2n-1) — (-(n-i-1)) = 3n-i-2

Result:

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