Python traverses all files in a folder

How python traverses all files in a folder: first open the corresponding code file; then traverse all files through "for f in files:print(os.path.join(root, f))" Just clip it.

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python traverses all files in the folder

Basic

import os
# 遍历文件夹
def walkFile(file):
    for root, dirs, files in os.walk(file):
        # root 表示当前正在访问的文件夹路径
        # dirs 表示该文件夹下的子目录名list
        # files 表示该文件夹下的文件list
        # 遍历文件
        for f in files:
            print(os.path.join(root, f))
        # 遍历所有的文件夹
        for d in dirs:
            print(os.path.join(root, d))
def main():
    walkFile("f:/ostest/")
if __name__ == '__main__':
    main()

Advanced

Calculate the number of lines of code in the py file in the folder

total_num = 0
for base_path,folder_list,file_list in os.walk(target_path):
    for file_name in file_list:
        file_path = os.path.join(base_path,file_name)
        file_ext = file_path.rsplit('.',maxsplit=1)
        if len(file_ext) != 2:
            # 没有后缀名
            continue
        if file_ext[1] != 'py':
            # 不是py文件
            continue
        file_num = 0
        with open(file_path,'rb') as f:
            for line in f:
                # 去空格
                line = line.strip()
                if not line:
                    continue
                # 去除 # 注释
                if line.startswith(b'#'):
                    continue
                file_num += 1
        total_num += file_num

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