How to replace newlines in php: 1. Use the "str_replace" function that comes with php to replace newlines; 2. Use regular expressions to replace newlines; 3. Use variables defined by php to Implement replacement line breaks.
Recommendation: "PHP Tutorial"
PHP replace newline character
First type:
The code is as follows:
<?php ?$str="this is a test \n"; $patten = array("\r\n", "\n", "\r"); ?//先替换掉\r\n,然后是否存在\n,最后替换\r $str=str_replace($order, "", $str); ?> //php 有三种方法来解决 //1、使用str_replace 来替换换行 $str = str_replace(array("\r\n", "\r", "\n"), "", $str); //2、使用正则替换 $str = preg_replace('//s*/', '', $str); //3、使用php定义好的变量 (建议使用) $str = str_replace(PHP_EOL, '', $str);
The code is as follows:
/* * 获得用户操作系统的换行符,\n * @access public * @return string */ function get_crlf() { if (stristr($_SERVER['HTTP_USER_AGENT'], 'Win')) { $the_crlf = '\r\n'; } elseif (stristr($_SERVER['HTTP_USER_AGENT'], 'Mac')) { $the_crlf = '\r'; // for old MAC OS } else { $the_crlf = '\n';//权重大一点 } return $the_crlf; }
Note: When displaying the front page, use nl2br The newline becomes
Second example description:
I found an interesting thing:
$text="aaaa ccc"; $text=str_replace('\n‘,"",$text); $text=str_replace('\r‘,"",$text); $text=str_replace('\r\n‘,"",$text);
Normally, the above code should be able to replace the newline character Okay
But in fact it is not possible!
I’m very depressed. I tried many times but it just doesn’t work.
Finally changed to this
The code is as follows:
$text=str_replace("\n","",$text); $text=str_replace("\r","",$text); $text=str_replace("\r\n","",$text);
Everything is OK~~It turns out to be a problem of double quotes and single quotes! !
Double quotation marks are less efficient than single quotation marks, because when double quotation marks are parsed by PHP, they will also judge whether there are variables in them, but single quotation marks will not make this judgment, so generally speaking, there is no Whenever variables are involved, I always use single quotes. I didn’t expect that replacing the newline character this time would not work with single quotes...
Finally written in one sentence
The code is as follows:
$order = array("\r\n", "\n", "\r"); $replace = ''; $text=str_replace($order, $replace, $text);
This will replace the newline character!
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php把负数转为正整数的方法:1、使用abs()函数将负数转为正数,使用intval()函数对正数取整,转为正整数,语法“intval(abs($number))”;2、利用“~”位运算符将负数取反加一,语法“~$number + 1”。

实现方法:1、使用“sleep(延迟秒数)”语句,可延迟执行函数若干秒;2、使用“time_nanosleep(延迟秒数,延迟纳秒数)”语句,可延迟执行函数若干秒和纳秒;3、使用“time_sleep_until(time()+7)”语句。

php除以100保留两位小数的方法:1、利用“/”运算符进行除法运算,语法“数值 / 100”;2、使用“number_format(除法结果, 2)”或“sprintf("%.2f",除法结果)”语句进行四舍五入的处理值,并保留两位小数。

php字符串有下标。在PHP中,下标不仅可以应用于数组和对象,还可应用于字符串,利用字符串的下标和中括号“[]”可以访问指定索引位置的字符,并对该字符进行读写,语法“字符串名[下标值]”;字符串的下标值(索引值)只能是整数类型,起始值为0。

判断方法:1、使用“strtotime("年-月-日")”语句将给定的年月日转换为时间戳格式;2、用“date("z",时间戳)+1”语句计算指定时间戳是一年的第几天。date()返回的天数是从0开始计算的,因此真实天数需要在此基础上加1。

在php中,可以使用substr()函数来读取字符串后几个字符,只需要将该函数的第二个参数设置为负值,第三个参数省略即可;语法为“substr(字符串,-n)”,表示读取从字符串结尾处向前数第n个字符开始,直到字符串结尾的全部字符。

方法:1、用“str_replace(" ","其他字符",$str)”语句,可将nbsp符替换为其他字符;2、用“preg_replace("/(\s|\ \;||\xc2\xa0)/","其他字符",$str)”语句。

php判断有没有小数点的方法:1、使用“strpos(数字字符串,'.')”语法,如果返回小数点在字符串中第一次出现的位置,则有小数点;2、使用“strrpos(数字字符串,'.')”语句,如果返回小数点在字符串中最后一次出现的位置,则有。


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