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Purpose:
First create an array with a length of 5, then assign a random integer to each bit of the array, and find the smallest (largest) value come out.
Method 1:
int array[] = new int[5]; System.out.println("数组的元素为:"); for (int i=0;i<array.length;i++){ array[i] = (int) (Math.random()*100); System.out.println(array[i]); } System.out.println("----------------------------------------------------"); int min = array[0]; for(int i=1;i<array.length;i++) { if(min>array[i]){ min=array[i]; } } System.out.println("方法二:最小值为:"+min); }
Result:
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Method 2:int array[] = new int[5]; System.out.println("数组的元素为:"); for (int i=0;i<array.length;i++){ array[i] = (int) (Math.random()*100); System.out.println(array[i]); } System.out.println("----------------------------------------------------"); //对数组进行排序处理 Arrays.sort(array); System.out.println("方法三:最小值为:"+array[0]); }Result:
##Method 3:
Collections through Collections class .max() and Collections.min() methods to find the maximum and minimum values in an array.
The code is as follows:
Integer array[] = new Integer[5]; System.out.println("数组的元素为:"); for (int i=0;i<array.length;i++){ array[i] = (int) (Math.random()*100); System.out.println(array[i]); } System.out.println("----------------------------------------------------"); //通过 Collections 类的 Collections.max() 和 Collections.min() 方法来查找数组中的最大和最小值: int min = (int)Collections.min(Arrays.asList(array)); int max = (int) Collections.max(Arrays.asList(array)); System.out.println("方法四:最小值为:"+min); System.out.println("方法四:最大值为:"+max);
Result:
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