Is it correct that the address bus width determines the physical address space that the CPU can access?

#Is it correct that the address bus width determines the physical address space that the CPU can access?

The address bus width determines the physical address space that the CPU can access.

Address bus width The address bus width determines the physical address space that the CPU can access. Simply put, it is how much memory the CPU can use. We need not talk about 16-bit microcomputers, but for microcomputer systems above 386, the width of the address line is 32 bits, and up to 4096 MB (4GB) of physical space can be directly accessed. Pentium Pro/Pentium II/Pentium III are 36-bit and can directly access 64GB of physical space.

The number of bits in the address bus determines the size of the memory space that the CPU can directly address. For example, the address bus of an 8-bit microcomputer is 16 bits, then its maximum addressable space is 2^16=64KB, 16 bits The address bus of the microcomputer is 20 bits, and its addressable space is 2^20=1MB. Generally speaking, if the address bus is n bits, the addressable space is 2^n bits.

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