首先看图:
第一步:首先对图像进行解析
想要打印该图形必须要进行多层循环嵌套,分两个部分进行打印。
第一部分为上半部分前四行,他们是递增的关系,后半部分后三行为递减关系,由此可以得出我们需要写两个打的循环。并且由于“*”位置的关系,我们必须带入空格同时打印。所以每个部分需要两个循环控制,即两个大循环每个里面嵌套两个小循环总计四个循环。
(相关教程推荐:java入门教程)
第二部:对数字进行分析
在分析之前,我们必须明白外层循环控制行数,内层循环控制列数,因此我们需要分析他的行和列。
示例代码如下:
class ForForTest { public static void main(String[] args) { /* 输出如下图形: 行数i: 空格数j: “*”数目z: * 1 3 1 *** 2 2 3 ***** 3 1 5 ******* 4 0 7 ***** 1 1 5 6 *** 2 2 3 5 * 3 3 1 4 */ for (int i = 1;i <= 4;i++){ for (int j = 1;j <= 4 - i;j++) { System.out.print(" "); } for (int z = 1;z <= i*2-1;z++){ System.out.print("*"); } System.out.println(); } for (int i = 1;i <= 3;i++){ for (int j = 1;j <= i;j++){ System.out.print(" "); } int y = 3; for (int z = 5;z >= 2*i-1;z--){ System.out.print("*"); } System.out.println(); } } }
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