java recursive algorithm example

Three elements of recursion:

1. Clarify the recursion termination conditions;

2. Give the handling method when the recursion terminates;

3. Extract repeated logic and reduce the size of the problem.

1, 1 2 3 … n

import java.util.Scanner;

public class Recursion {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        System.out.println(sum(n));
    }

    public static int sum(int n) {
        if(n == 1) {
            return n;
        }
        else {
            return n + sum(n-1);
        }
    }
}

2, 1 * 2 * 3 * … * n

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import java.util.Scanner;

public class Recursion {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        System.out.println(multiply(n));
    }

    public static int multiply(int n) {
        if(n == 1) {
            return n;
        }
        else {
            return n*multiply(n-1);
        }
    }
}

3. Fibonacci Sequence

The first two items are both 1. Starting from the third term, each term is equal to the sum of the previous two terms. That is: 1, 1, 2, 3, 5, 8,…

import java.util.Scanner;

public class Recursion {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();

        System.out.println(fun(n));
    }

    public static int fun(int n) {

        if (n <= 2) {
            return 1;
        }
        else {
            return fun(n-1) + fun(n-2);
        }
    }
}

4. Binary tree traversal (before, during and after)

import java.util.Arrays;
import java.util.LinkedList;

public class MyBinaryTree {
    //二叉树节点
    private static class TreeNode{
        int data;
        TreeNode leftChild;
        TreeNode rightChile;

        public TreeNode(int data) {
            this.data = data;
        }
    }

    //构建二叉树
    public static TreeNode createBinaryTree(LinkedList<Integer> inputList) {
        TreeNode node = null;
        if(inputList == null || inputList.isEmpty()) {
            return null;
        }
        Integer data = inputList.removeFirst();

        //如果元素为空，则不再递归
        if(data != null){
            node = new TreeNode(data);
            node.leftChild = createBinaryTree(inputList);
            node.rightChile = createBinaryTree(inputList);
        }
        return node;
    }

    //前序遍历:根节点，左子树，右子树
    public static void preOrderTraveral(TreeNode node) {
        if (node == null) {
            return;
        }
        System.out.println(node.data);
        preOrderTraveral(node.leftChild);
        preOrderTraveral(node.rightChile);
    }

    //中序遍历：左子树，根节点，右子树
    public static void inOrderTraveral(TreeNode node) {
        if(node == null) {
            return;
        }

        inOrderTraveral(node.leftChild);
        System.out.println(node);
        inOrderTraveral(node.rightChile);

    }

    //后序遍历：左子树，右子树，根节点
    public static void postOrderTraveral(TreeNode node) {
        if (node == null) {
            return;
        }

        postOrderTraveral(node.leftChild);
        postOrderTraveral(node.rightChile);
        System.out.println(node.data);
    }

    public static void main(String[] args) {
       LinkedList<Integer> inputList = new LinkedList<Integer>(Arrays.asList(new Integer[]{3,2,9,null,null,10,null,null,8,null,4}));
       TreeNode treeNode = createBinaryTree(inputList);
       System.out.println("前序遍历：");
       preOrderTraveral(treeNode);

        System.out.println("中序遍历：");
        inOrderTraveral(treeNode);

        System.out.println("后序遍历：");
        postOrderTraveral(treeNode);
    }
}

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