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Because we often need to get part of the text in the string after fetching the source code of the web page, but I don’t know how to use regular expressions. The expressions I write often cannot get the desired content, so I wrote a function myself, which can basically get to the desired text.
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1. Implementation function
/* *取字符串中间文本 * @paramstring$str需要处理的字符串 * @paramstring $start_str 目标字符串‘前’的字符 * @paramstring $stop_str 目标字符串‘后’的字符 * @paramint $count 需要查找的次数 * @paramint $n 从第n个位置开始查找 * @returnarray$data返回查找满足条件要求的数组字符串 */ function get_msg($str,$start_str,$stop_str,$count,$n){ $start=$n; //从第n个位置开始查找 $data=array(); for($i=0;$i<$count;$i++){ $start=strpos($str,$start_str,$start); $stop=strpos($str,$stop_str,$start); $start=strlen($start_str)+$start; $data[$i]= substr($str,$start,$stop-$start); $start=$stop; } return $data; }
2. Implementation example
<?php $stra = "你看这是一个字符串"; $strb = "你看这依然是个字符串,你看这依然是个字符串,你看这个依然就取不到"; $resultArra = get_msg($stra,"你看","符串",1,0); //从第0个位置开始查找,取目标 '这是一个字' ,并且查找1次 $resultArrb = get_msg($strb,"你看这","是个",3,0);//从第0个位置开始查找,取目标 '依然' ,并且查找3次 print_r($resultArra); print_r($resultArrb); function get_msg($str, $start_str, $stop_str, $count, $n) { $start=$n; //从第n个位置开始查找 $data=array(); for($i=0;$i<$count;$i++){ $start=strpos($str,$start_str,$start); $stop=strpos($str,$stop_str,$start); $start=strlen($start_str)+$start; $data[$i]= substr($str,$start,$stop-$start); $start=$stop; } return $data; } ?>
Return result
Array ( [0] => 这是一个字 ) Array ( [0] => 依然 [1] => 依然 [2] => )
Although there are three 'still' characters in the second string $strb, only two of them meet the conditions passed into the function, so only two that meet the conditions will be found.
Of course this is just a simple example, more complex strings can also be used, just pass in the corresponding conditions.
3. Search for the nth occurrence of characters and strings
This can be used in conjunction with the above function, depending on the requirements
/*查找字符、字符串第n次出现的位置 *@param string $str 原始字符串 *@param string $find需要查找的字符、字符串 *@param int $n第几次出现的字符、字符串 *@return int $count返回第n次出现的位置 */ function str_n_pos($str,$find,$n){ for ($i=1;$i<=$n;$i++){ $pos = strpos($str,$find); $str = substr($str,$pos+1); $pos_val=$pos+$pos_val+1; } $count = $pos_val-1; return $count; }
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