Method 1:
You can use the binarySearch(Object[] a, Object key)
method in the Arrays
class to Finds whether a certain value exists. If a certain value exists, the return value is greater than 0, otherwise the return value is less than 0.
Advantages: Use binary search method, fast and efficient.
Disadvantages: The queried array must be ordered. If it is not ordered, using this method is useless.
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Example:
String[] array = {"1","2","3","4"}; int index = Arryas.binarySearch(array,"2"); System.out.println("index:" + index); //--- index:1 index = Arryas.binarySearch(array,"0"); System.out.println("index:" + index); //--- index:-1 index = Arryas.binarySearch(array,"5"); System.out.println("index:" + index); //--- index:-5
Method 2:
Use Arrays
The asList()
method in the class converts the array into a List() list, and then uses the contains()
method to determine whether a certain value exists in the array.
Advantages: Arrays can be out of order and there is no order requirement.
Disadvantages: The query efficiency may be slightly slower, but it should not affect the overall situation.
Example:
String[] array = {"1","2","3","4"}; boolean flag = Arrays.asList(array).contains("2"); System.out.println("flag:" + flag);//--- flag:true flag = Arrays.asList(array).contains("0"); System.out.println("flag:" + flag);//--- flag:false flag = Arrays.asList(array).contains("5"); System.out.println("flag:" + flag);//--- flag:false
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