How to use regular expressions to filter special characters in java
实例代码如下:
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public class FilterSpecialStr { public static void main(String[] args) { String regEx="[\n`~!@#$%^&*()+=|{}':;',\\[\\].<>/?~!@#¥%……&*()——+|{}【】‘;:”“’。, 、?]"; // 除了字母数字下划线之外的字符为非法字符 Pattern pattern = Pattern.compile(regEx); // 指定设置非法字符 // Pattern pattern = Pattern.compile("[@#]"); String str = "123@abc {} \n #D EF。"; Matcher matcher = pattern.matcher(str); StringBuffer buffer = new StringBuffer(); //如果找到非法字符 while (matcher.find()) { // 如果里面包含非法字符如冒号双引号等,那么就把他们消去,并把非法字符前面的字符放到缓冲区 matcher.appendReplacement(buffer, ""); } // 将剩余的合法部分添加到缓冲区 matcher.appendTail(buffer); System.out.println("过滤前的字符: " + str); System.out.println("过滤后的字符: " + buffer.toString()); } }
输出的结果:
过滤前的字符: 123@abc {}
#D EF。
过滤后的字符: 123abcDEF
java相关文章教程:java语言入门
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