This article mainly introduces to you the methods of querying and deleting duplicate records in MySQL, and shares it for your reference and study. Let’s take a look at the detailed introduction below.
Find all records with duplicate titles:
select title,count(*) as count from user_table group by title having count>1;
SELECT * FROM t_info a WHERE ((SELECT COUNT(*) FROM t_info WHERE Title = a.Title) > 1) ORDER BY Title DESC
1. Find duplicate records
1. Find all duplicate records
SELECT * FROM t_info a WHERE ((SELECT COUNT(*) FROM t_info WHERE Title = a.Title) > 1) ORDER BY Title DESC
2. Filter duplicate records (only display one)
Select * From HZT Where ID In (Select Max(ID) From HZT Group By Title)
Note: The record with the largest ID is displayed here
2. Delete duplicate records
1. Delete all duplicate records (Use with caution)
Delete 表 Where 重复字段 In (Select 重复字段 From 表 Group By 重复字段 Having Count(*)>1)
2 , keep one record (this should be what most people need^_^)
Delete HZT Where ID Not In (Select Max(ID) From HZT Group By Title)
Note: Keep the record with the largest ID here
3. Example
1. Find redundant duplicate records in the table. Duplicate records are judged based on a single field (peopleId).
select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
2. Delete redundant duplicate records in the table. , duplicate records are judged based on a single field (peopleId), and only the record with the smallest rowid is left
delete from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)
3. Lookup the redundant duplicate records (multiple fields) in the lookup table
select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
4. Delete the redundant duplicate records (multiple fields) in the table, leaving only the record with the smallest rowid.
delete from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
5. Find the redundant duplicate records (multiple fields) in the table, excluding the record with the smallest rowid. Record
select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
4. Supplement
There are more than two duplicate records. The first is a completely duplicate record, that is, a record in which all fields are repeated, and the second is a partial duplicate record. Records with repeated key fields, such as the repeated Name field, but other fields may not be repeated or can be ignored.
1. For the first type of duplication, it is relatively easy to solve. Use
select distinct * from tableName
to get a result set without duplicate records.
If the table needs to delete duplicate records (retain 1 duplicate record), you can delete it as follows
select distinct * into #Tmp from tableName drop table tableName select * into tableName from #Tmp drop table #Tmp
The reason for this duplication is poor table design. Add unique Index column can be solved.
2. This type of duplication problem usually requires retaining the first record among the duplicate records. The operation method is as follows
Assume that the duplicate fields are Name and Address, and it is required to obtain the uniqueness of these two fields. The result set
select identity(int,1,1) as autoID, * into #Tmp from tableName select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID select * from #Tmp where autoID in(select autoID from #tmp2)
Summary
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Recommended learning: MySQL tutorial
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