One: Use List
public static boolean useList(String[] arr, String targetValue) { return Arrays.asList(arr).contains(targetValue); }
Two: Use Set
public static boolean useSet(String[] arr, String targetValue) { Set<String> set = new HashSet<String>(Arrays.asList(arr)); return set.contains(targetValue); }
Three: Use loop judgment
public static boolean useLoop(String[] arr, String targetValue) { for(String s: arr){ if(s.equals(targetValue)) return true; } return false; }
Four: Use Arrays.binarySearch()
Arrays.binarySearch()
The method can only be used for ordered arrays! ! ! If the array is unordered, the results will be strange.
The usage of finding whether an ordered array contains a certain value is as follows:
public static boolean useArraysBinarySearch(String[] arr, String targetValue) { int a = Arrays.binarySearch(arr, targetValue); if(a > 0) return true; else return false; }
Recommended tutorial: java quick start
The above is the detailed content of Java determines whether an array contains an element. For more information, please follow other related articles on the PHP Chinese website!