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What is method overloading in java?
Method overloading means that there can be multiple methods with the same name in a class, but the parameters of these methods must be different. Advantages: You only need to remember a single method name to achieve multiple similar functions.
What needs to be noted here is that different parameters need to meet two conditions. One is that the number of parameters is different, and the other is that the number of parameters is the same, but the type of a corresponding parameter in the parameter list is different.
The overloading of methods is related to the following factors:
1. Different number of parameters
2. Different parameter types
3. Multiple types of parameters The order is different
The overloading of the method has nothing to do with the following factors:
1. It has nothing to do with the name of the parameter
2. It has nothing to do with the return value type of the method
Example:
Question requirement: Compare two data to see if they are equal.
The parameter types are two byte types, two short types, two int types, and two long types.
And test it in the main method
public class CaiNiao{ public static void main(String[] args){ byte a = 10; byte b = 20; System.out.println(isSame(a,b)); System.out.println((isSame(short)20,(short)20)); System.out.println(isSame(11,22)); System.out.println(isSame(10L,10L)); } public static boolean isSame(byte a,byte b){ System.out.println("两byte参数的方法执行!"); boolean same ; if(a==b){ same = true; }else{ same = false; } return same; } public static boolean isSame(short a,short b){ System.out.println("两short参数的方法执行!"); boolean same = a == b ?true:false; return same; } public static boolean isSame(int a,int b){ System.out.println("两int参数的方法执行!"); return a == b:; } public static boolean isSame(long a,long b){ System.out.println("两long参数的方法执行!"); if (a==b){ return true; } else{ return false; } } }
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