PHP determines whether it is a leap year

1, PHP leap year calculation method 1:

The leap year is when the remainder of 4 is 0, the remainder of 100 is not equal to 0, and the remainder of 400 is equal to 0 The year is a leap year.

$day = date('Y');
if ($day%4==0&&($day%100!=0 || $day%400==0)){
    echo $day.'是闰年';
}else{
    echo $day.'不是闰年';
}

2, PHP method two to determine leap year:

date('L'); you can directly determine whether the current year is a leap year, return 1 if true, otherwise return 0.

$year = 2008;//可以像上例一样用mt_rand随机取一个年，也可以随便赋值。
$time = mktime(20,20,20,4,20,$year);//取得一个日期的 Unix 时间戳;
if (date("L",$time)==1){ //格式化时间，并且判断是不是闰年，后面的等于一也可以省略；
echo $year."是闰年";
}else{
echo $year."不是闰年";
}

3, PHP’s third method of judging leap years and calculating leap years:

$year = 2000;
$time = mktime(20,20,20,2,1,$year);//取得一个日期的 Unix 时间戳;
if (date("t",$time)==29){ //格式化时间，并且判断2月是否是29天；
echo $year."是闰年";//是29天就输出时闰年；
}else{
echo $year."不是闰年";
}

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