PHP determines whether it is a normal year or a leap year

The Gregorian calendar's rules for determining leap years are: there is a leap every four years, there are no leaps every hundred years, and there are leaps every four hundred years.

The natural way to write it is as follows: (Recommended learning: PHP video tutorial)

$year=2015;
if(($year%4 == 0 && $year%100 != 0) || ($year%400 == 0 )) {
echo "$year is run yerar. 
";
}else {
 
echo "$year is ping year. 
";
}

Method 2: There are two types

(1). An ordinary year that can be divisible by 4 but not divisible by 100 is a leap year. (For example, 2004 is a leap year, and 1900 is not a leap year)

(2). A century year that is divisible by 400 but not divisible by 3200 is a leap year. (For example, the year 2000 is a leap year, and the year 3200 is not a leap year)

Code:

$year=mt_rand(1900,2200);//从1900年到2200，可以自己改，也可以给一个定值。
if($year%100==0){//判断世纪年
if ($year%400==0&&$year%3200!=0){
   echo "世纪年".$year."是闰年!";//世纪年里的闰年
}
else{echo "世纪年".$year."不是闰年!";}
}
else{//剩下的就是普通年了
   if($year%4==0&&$year%100!=0){
   echo "普通年".$year."是闰年!";//普通年里的闰年
}
else {echo "普通年".$year."不是闰年!";}
}

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