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The solution to the problem that ajax cannot get the php return value:
1. First check whether ajax is It is asynchronous. Async cannot directly return the result.
/*常见错误示例 直接在 ajax 里面return 结果*/ function demo(){ $.ajax({ url : 'test.do', type : "post", data : {}, async : false, success : function(data) { return 2; } }); }/* 结果 无返回 */
2. Then ensure that ajax does not return data in the nested function. The function that calls ajax should return the data.
/** * (1)同步调用 (2)且在ajax对全局变量进行设值 (3)ajax函数外将变量return * 结果:返回 2。成功获取返回值 * 成功原因:先执行result = 2;再往下执行return result; */ function demo1(){ var result = 1; $.ajax({ url : 'test.do', type : "post", data : {}, async : false, success : function(data) { result = 2; } }); return result; //2 }
3. It can run normally. However, changing ajax to a synchronous request will cause blocking; ajax requires an asynchronous request.
/** * 添加async:true.即修改为异步 * 结果以callback的形式回调 */ function demo1(params,callback){ var result = 1; $.ajax({ url : 'test.do', type : "post", data : {"params ":params }, async : true, success : function(data) { result = 2; callback(result); } }); } demo1("Value",function(rs){ //do someting })
Note: The php requested by ajax requires echo or print data, otherwise ajax will not be able to obtain the data.
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