ajax+php做的search，显示和关闭的问题？
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- 2016-05-22 18:35:58822browse
我用ajax+php作了个简易的类似于google search的搜索，当我没输入字母的时候，显示是这样的，1.jpg:
当我输入字母时显示是，2.jpg的效果。
请问大家，当我鼠标点击别处时，使弹出的search的那个框自动关闭，应如何修改，代码如下
<html>
<body>
<style type="text/css">
#livesearch
{
margin:0px;
width:140px;
}
#txt1
{
margin:0px;
}
</style>
<script type="text/javascript">
var xmlHttp
function showResult(str) {
if (str.length == 0) {
document.getElementById("livesearch").
innerHTML = "";
document.getElementById("livesearch").
style.border = "0px";
return
}
xmlHttp = GetXmlHttpObject()
if (xmlHttp == null) {
alert("Browser does not support HTTP Request")
return
}
var url = "suggest_list.php"
url = url + "?q=" + str
url = url + "&sid=" + Math.random()
xmlHttp.onreadystatechange = stateChanged
xmlHttp.open("GET", url, true)
xmlHttp.send(null)
}
function stateChanged() {
if (xmlHttp.readyState == 4 || xmlHttp.readyState == "complete") {
document.getElementById("livesearch").
innerHTML = xmlHttp.responseText;
document.getElementById("livesearch").
style.border = "1px solid #999999";
}
}
function GetXmlHttpObject() {
var xmlHttp = null;
try {
// Firefox, Opera 8.0+, Safari
xmlHttp = new XMLHttpRequest();
} catch (e) {
// Internet Explorer
try {
xmlHttp = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
}
}
return xmlHttp;
}
</script>
<form>
<TABLE align="center" style="margin-top:140px" >
<TR>
<TD>
<input type="text" id="txt1" size="26" name="username">
<div id="livesearch"></div>
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</TD>
</tr>
</TABLE>
</form>
</body>
</html>本文地址：
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