Home  >  Article  >  Backend Development  >  How to call api interface in python

How to call api interface in python

爱喝马黛茶的安东尼
爱喝马黛茶的安东尼Original
2019-06-13 17:33:5829093browse

How python calls the api interface:

Interface protocol: http, webservice, rpc, etc.

Request method: get, post method

Request parameter format:

a. Get requests are all through url?param=xxx¶m1=xxx

b. Common types of request parameters for post requests include: application/json, application/x-www-form-urlencoded, multipart/form-data, text/html, etc.

You also need to know the url of the interface, parameter type, data format of the returned result, and whether the interface has header, cookie and other information.

Related recommendations: "python video tutorial"

How to call api interface in python

##get method

# coding:utf-8 
import json
from urlparse import parse_qs
from wsgiref.simple_server import make_server  
# 定义函数,参数是函数的两个参数,都是python本身定义的,默认就行了。
def application(environ, start_response):
    # 定义文件请求的类型和当前请求成功的code
    start_response('200 OK', [('Content-Type', 'text/html')])
    # environ是当前请求的所有数据,包括Header和URL,body,这里只涉及到get
    # 获取当前get请求的所有数据,返回是string类型
    params = parse_qs(environ['QUERY_STRING'])
    # 获取get中key为name的值
    name = params.get('name', [''])[0]
    no = params.get('no', [''])[0] 
    # 组成一个数组,数组中只有一个字典
    dic = {'name': name, 'no': no} 
    return [json.dumps(dic)]  
if __name__ == "__main__":
    port = 5088
    httpd = make_server("0.0.0.0", port, application)
    print "serving http on port {0}...".format(str(port))
    httpd.serve_forever()

Request instance

How to call api interface in python

post method

# coding:utf-8 
import json
from wsgiref.simple_server import make_server
# 定义函数,参数是函数的两个参数,都是python本身定义的,默认就行了。
def application(environ, start_response):
    # 定义文件请求的类型和当前请求成功的code
    start_response('200 OK', [('Content-Type', 'application/json')])
    # environ是当前请求的所有数据,包括Header和URL,body
    request_body = environ["wsgi.input"].read(int(environ.get("CONTENT_LENGTH", 0)))
    request_body = json.loads(request_body)
    name = request_body["name"]
    no = request_body["no"]
    # input your method here
    # for instance:
    # 增删改查
    dic = {'myNameIs': name, 'myNoIs': no}
    return [json.dumps(dic)]
if __name__ == "__main__":
    port = 6088
    httpd = make_server("0.0.0.0", port, application)
    print "serving http on port {0}...".format(str(port))
    httpd.serve_forever()

Request instance

How to call api interface in python

The above is the detailed content of How to call api interface in python. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn