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How to use different delimiters to split a string, split a string according to the delimiter, the character contains different delimiters, as follows
s = '12;;7.osjd ;.jshdjdknx ' where; . is the separator
What are the solutions?
Method 1: Through the str.split() method, process one separator at a time
#!/usr/bin/python3 def go_split(s, symbol): result = [s] for i in symbol: median = [] # 普通方法 # for x in result: # median.extend(x.split(i) # 列表解析 # [median.extend(y.split(i)) for y in result if y] # map高阶函数,map生成可迭代对象 for z in map(lambda x: x.split(i), result): median.extend(z) # 以上三个方法都可以解决问题 result = median # 去除空字符串 return [x for x in result if x] if __name__ == "__main__": # 定义初始字符串 s = '12;;7.osjd;.jshdjdknx+' # 定义分隔符 symbol = ';./+' result = go_split(s, symbol) print(result)
Method 2: Through the re.split() method, Split all strings at once, recommended
#!/usr/bin/python3 import re def go_split(s, symbol): # 拼接正则表达式 symbol = "[" + symbol + "]+" # 一次性分割字符串 result = re.split(symbol, s) # 去除空字符 return [x for x in result if x] if __name__ == "__main__": # 定义初始字符串 s = '12;;7.osjd;.jshdjdknx+' # 定义分隔符 symbol = ';./+' result = go_split(s, symbol) print(result)
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