How to determine whether a file is hidden in Java? (code example)
In Java, we can use the isHidden() method of the File class to determine whether the specified file is hidden; the following article will introduce you to the isHidden() method and learn how to use the isHidden() method to determine whether the file is hidden. Hidden, hope it helps everyone.
isHidden() method
The isHidden() method of the File class is used to check the specified file. Whether it is a hidden file; it returns a Boolean value, true if the file is hidden, false otherwise.
Basic syntax:
file.isHidden()
file: Indicates the file to be tested
Description:
Judgment Whether a file is considered hidden or not, the exact definition of hidden depends on the platform or provided program. For example, on UNIX, a file is considered hidden if its name begins with a period character ("."). On Windows, a file is considered hidden if it is not a directory and the DOS hidden attribute is set.
Depending on the actual situation, the isHidden() method may need to access the file system to determine whether the file is considered hidden.
How to use the isHidden() method to determine whether a file is hidden?
Code example:
import java.io.File; import java.io.IOException; public class HiddenPropertyCheck { public static void main(String[] args) throws IOException, SecurityException { // 指定文件,提供完整的文件路径 File file = new File("c:/myfile.txt"); if(file.isHidden()){ System.out.println("指定的文件被隐藏"); }else{ System.out.println("指定的文件未隐藏"); } } }
Output:
指定的文件未隐藏
Description: throws followed by
IOException: Indicates if an I/O error occurs
SecurityException: Indicates that if it is the default provider and a security manager is installed, the checkRead method is called to check read access to the file.
Recommended video tutorials: "Java Tutorial"
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