Use PHP to process image file uploads

This article mainly introduces the use of PHP to process image file uploads. It has certain reference value. Now I share it with everyone. Friends in need can refer to

1.html file

Form form attention. enctype attribute

<form action="goods/goodsAdd.action.php" method="POST" enctype="multipart/form-data">

Code:

	
添加商品

	<form action="goods/goodsAdd.action.php" method="POST" enctype="multipart/form-data">

		

			

				商品名

				
			

			

				商品价格

				
			

			

				商品库存

				
			

			

				
产品分类

				
					{$rowClass['name']}";

							$sqlBrand = "select * from brand where sort_id='{$rowClass[id]}' ";

							$rstBrand = mysqli_query($conn,$sqlBrand);

							while ($rowBrand=mysqli_fetch_assoc($rstBrand)) {
								
								echo "  |-{$rowBrand['name']}";
							}
						}
					?>
				
			

			


				
货架

				上架s

				

				下架d

				
			

			

				
			

		

		

	

View data:

    echo "<pre class="brush:php;toolbar:false">";

      print_r($_POST);

      echo "

"; echo "

";

      print_r($_FILES);

      echo "

"; exit;

The test is as shown:

. PHP file code:

<?php
  
	require(&#39;../../public/common/config.php&#39;);

      // echo "<pre class="brush:php;toolbar:false">";

      // print_r($_POST);

      // echo "

"; // echo "

";

      // print_r($_FILES);

      // echo "

"; // exit; $name = $_POST['goodsname']; $price = $_POST['goodsprice']; $sort = $_POST['goodsort']; $shelf = $_POST['shelf']; $brand_id = $_POST['brand_id']; //图片上传 $src = $_FILES['img']['tmp_name']; $name = $_FILES['img']['name']; $ext = array_pop(explode('.', $name)); $dst = '../../public/uploads/'.time().mt_rand().'.'.$ext; if(move_uploaded_file($src, $dst)){ echo "upload success"; //图片缩放200*200 }else{ echo "upload error"; } ?>

Related recommendations:

php method example of uploading image files in post mode

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