PHP returns a JSON object to the front end

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Solution to the problem: When using PHP as the backend, how to return an "object" in JSON format to the AJAX request initiated by the front end;

Explanation: I I am a front-end person myself. After working for a long time, I found that if I don’t master a back-end development language, I always feel a little powerless. Recently, I was learning PHP while working on my own personal website. When writing

Verification Code for verification, I needed to return an easy-to-operate data to the verification request initiated by the front end, so I naturally thought of returning a JSON format. "object".

I checked a lot of writing methods on the Internet, but most of them didn't work. Finally, I found the reason on stack

overflow and rewrote the code. I personally tested it and it worked, so I recorded it, hoping to be helpful to others in the future. .

The code is as follows:

<?php
	/*验证验证码是否正确*/
	session_start();
	$code = trim($_POST[&#39;code&#39;]);//接收前端传来的数据
	$raw_success = array(&#39;code&#39; => 1, &#39;msg&#39; => &#39;验证码正确&#39;);
	$raw_fail = array(&#39;code&#39; => 2, &#39;msg&#39; => &#39;验证码错误&#39;);
	
	$res_success = json_encode($raw_success);
	$res_fail = json_encode($raw_fail);
	
	header(&#39;Content-Type:application/json&#39;);//这个类型声明非常关键
	if ($code == $_SESSION["verfycode"]) {
		echo $res_success;
	} else {
		echo $res_fail;
	}
?>

In this way, the data received by the front-end is an object, and the front-end operation is very convenient.

If the verification is successful, the response will be

{code:1,msg:"Verification code is correct"};If the verification fails, {code:2,msg:"Verification code is incorrect" ｝;

Because I am not a professional PHP developer, so someone has seen it and has a better way, please give me some advice, thank you!

Related recommendations:

JSON PHP, the method of deserializing Json string into an object/array

PHP uses Method to return requested data in json or xml format

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