In JSON PHP, how to deserialize Json string into object/array

This article mainly introduces the method of deserializing JSON strings into objects/arrays in JSON PHP. It has certain reference value. Now I share it with you. Friends in need can refer to it

is as follows:

<?php
//php反编码解析json信息
//json_decode(json字符串);
$city = array(&#39;shandong&#39;=>&#39;jinan&#39;,&#39;henan&#39;=>&#39;zhengzhou&#39;,&#39;hebei&#39;=>&#39;shijiazhuang&#39;);
$jn_city = json_encode($city);
//反编码json
$fan_city = json_decode($jn_city,false);//第二个参数false则返回object类型，false可以默认不写
var_dump($fan_city);//object(stdClass)#1 (3) { ["shandong"]=> string(5) "jinan" ["henan"]=> string(9) "zhengzhou" ["hebei"]=> string(12) "shijiazhuang" } 
echo "<br />";
$fan_city = json_decode($jn_city,true);//第二个参数true则返回array类型
var_dump($fan_city);//array(3) { ["shandong"]=> string(5) "jinan" ["henan"]=> string(9) "zhengzhou" ["hebei"]=> string(12) "shijiazhuang" }

##The manually written JSON string must use single quotes. Successfully deserialized into object/array:

<?php 
 
//json信息反编码 
 
//不同php版本，对“纯json字符串”解析存在问题 
//使用双引号定义的json字符串反编码操作变为null 
//$jn = "{&#39;name&#39;:&#39;tom&#39;,&#39;age&#39;:&#39;20&#39;,&#39;addr&#39;:&#39;beijing&#39;}"; 
//$fan_jn = json_decode($jn,true); 
//var_dump($fan_jn);//NULL 
 
//使用单引号定义的json字符串反编码操作会成功 
$jn = &#39;{"name":"tom","age":"20","addr":"beijing"}&#39;; 
$fan_jn = json_decode($jn,true); 
var_dump($fan_jn);

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