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JSPrototype modification and rewriting
There are two ways to modify the js prototype:
1. In the original prototype Add properties and methods to the object: 12
function Person(){ } Person.prototype.name="Mike"; Person.prototype.sayName=function(){ console.log(this.name); } var person= new Person(); person.sayName(); //Mike123456789
2. Override or overwrite the prototype object: 12
function Person(){ } Person.prototype={ "name":"Mike", sayName:function(){ console.log(this.name); } } var person=new Person(); person.sayName(); //Mike1234567891011
Next let’s look at a question: (This question also explains the difference between adding properties and methods directly to the prototype object and overriding or overwriting the prototype object.) 12
function Person(){ } function Animal(){ } var person=new Person(); var animal=new Animal(); Person.prototype={ "name":"Mike", sayName:function(){ console.log(this.name); } } Animal.prototype.name="animal"; Animal.prototype.sayName=function(){ console.log(this.name); } person.sayName(); //error person.sayName is not a function animal.sayName();//animal1234567891011121314151617181920 分析:12 function Person(){ } function Animal(){ } var person=new Person(); var animal=new Animal(); console.log(person. proto ===Person.prototype); //true console.log(animal.proto===Animal.prototype); //true Person.prototype={ "name":"Mike", sayName:function(){ console.log(this.name); } } Animal.prototype.name="animal"; Animal.prototype.sayName=function(){ console.log(this.name); } console.log(person.proto===Person.prototype); //false console.log(animal.proto===Animal.prototype); //true person.sayName(); //error person.sayName is not a function animal.sayName();//animal
Above This is a JS rewriting prototype object that I compiled for you. I hope it will be helpful to you in the future.
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