This time I will bring you JS to retain one digit and then remove non-digits, and JS to retain one digit and then remove non-digits. What are the precautions?. Here is a practical case. Let’s take a look. one time.
//去除非数字 var clearNoNum = function (item) { if (item!=null && item!=undefined) { //先把非数字的都替换掉,除了数字和. item = item.replace(/[^\d.]/g, ""); //必须保证第一个为数字而不是. item = item.replace(/^\./g, ""); //保证只有出现一个.而没有多个. item = item.replace(/\.{2,}/g, ""); //保证.只出现一次,而不能出现两次以上 item = item.replace(".", "$#$").replace(/\./g, "").replace("$#$", "."); //最多保留小数点后一位 var arr = item.split("."); if (arr.length > 1) item = arr[0] + '.' + (arr[1].length > 1 ? arr[1].substr(0, 1) : arr[1]); } return item; }
Supplement:
Let’s take a look at js processing numbers to retain 2 decimal places. It is not enough to force 2 decimal places. Add .00
1, keep two decimal places //Function: round the floating point number, take 2 digits after the decimal point
2, //keep 2 digits For decimals, such as: 2, 00 will be added after 2. That is 2.00
nbsp;html> <meta> <title>Test</title> <script></script> <script> //保留两位小数 //功能:将浮点数四舍五入,取小数点后2位 function toDecimal(x) { var f = parseFloat(x); if (isNaN(f)) { return; } f = Math.round(x*100)/100; return f; } //制保留2位小数,如:2,会在2后面补上00.即2.00 function toDecimal2(x) { var f = parseFloat(x); if (isNaN(f)) { return false; } var f = Math.round(x*100)/100; var s = f.toString(); var rs = s.indexOf('.'); if (rs < 0) { rs = s.length; s += '.'; } while (s.length <= rs + 2) { s += '0'; } return s; } function fomatFloat(src,pos){ return Math.round(src*Math.pow(10, pos))/Math.pow(10, pos); } document.write("四舍五入 <br/>") document.write("3.14159267保留2位小数:" + toDecimal(3.14159267)+"<br/>"); document.write("3.14159267强制保留2位小数:" + toDecimal2(3.14159267)+"<br/>"); document.write("3.14159267保留2位小数:" + toDecimal(3.14559267)+"<br/>"); document.write("3.14159267强制保留2位小数:" + toDecimal2(3.15159267)+"<br/>"); document.write("3.14159267保留2位小数:" + fomatFloat(3.14559267, 2)+"<br/>"); document.write("3.14159267保留1位小数:" + fomatFloat(3.15159267, 1)+"<br/>"); document.write("五舍六入 <br/>") document.write("1000.003保留2位小数:" + 1000.003.toFixed(2)+"<br/>"); document.write("1000.08保留1位小数:" + 1000.08.toFixed(1)+"<br/>"); document.write("1000.04保留1位小数:" + 1000.04.toFixed(1)+"<br/>"); document.write("1000.05保留1位小数:" + 1000.05.toFixed(1)+"<br/>"); document.write("科学计数 <br/>") document.write(3.1415+"科学技术后:"+3.1415.toExponential(2)+"<br/>"); document.write(3.1455+"科学技术后:"+3.1455.toExponential(2)+"<br/>"); document.write(3.1445+"科学技术后:"+3.1445.toExponential(2)+"<br/>"); document.write(3.1465+"科学技术后:"+3.1465.toExponential(2)+"<br/>"); document.write(3.1665+"科学技术后:"+3.1665.toExponential(1)+"<br/>"); document.write("精确到n位,不含n位 <br/>") document.write("3.1415精确到小数点第2位" + 3.1415.toPrecision(2)+"<br/>"); document.write("3.1455精确到小数点第3位" + 3.1465.toPrecision(3)+"<br/>"); document.write("3.1445精确到小数点第2位" + 3.1415.toPrecision(2)+"<br/>"); document.write("3.1465精确到小数点第2位" + 3.1455.toPrecision(2)+"<br/>"); document.write("3.166592679287精确到小数点第5位" + 3.141592679287.toPrecision(5)+"<br/>"); </script> <input>
I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!
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