python delete files before specified time interval

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Traverse the files in the specified folder, and obtain the file list of the specified type according to the file suffix name; according to the file path in the file list, obtain the "modification time" in the file attributes one by one. If the difference between "modification time" and "current system time" is greater than a certain value, the file will be deleted.

#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""Document: Remove Synctoycmd sync expired .tmp files"""
import os
import time
import datetime
def diff():
  '''time diff'''
  starttime = datetime.datetime.now()
  time.sleep(10)
  endtime = datetime.datetime.now()
  print "time diff: %d" % ((endtime-starttime).seconds)
def fileremove(filename, timedifference):
  '''remove file'''
  date = datetime.datetime.fromtimestamp(os.path.getmtime(filename))
  print date
  now = datetime.datetime.now()
  print now
  print 'seconds difference: %d' % ((now - date).seconds)
  if (now - date).seconds > timedifference:
    if os.path.exists(filename):
      os.remove(filename)
      print 'remove file: %s' % filename
    else:
      print 'no such file: %s' % filename
FILE_DIR = 'D:/'
if __name__ == '__main__':
  print 'Script is running...'
  #diff()
  while True:
    ITEMS = os.listdir(FILE_DIR)
    NEWLIST = []
    for names in ITEMS:
      if names.endswith(".txt"):
        NEWLIST.append(FILE_DIR + names)
    #print NEWLIST
    for names in NEWLIST:
      print 'current file: %s' % (names)
      fileremove(names, 10)
    time.sleep(10)
  print "never arrive..."

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